⛄Snowberb⛄ – 11-14 Jan 10

⛄⛄Snowberb⛄

1/10/2023

Having data.length === 17 and limit === 10, how can I dynamically obtain the result of 3? As data.length and limit can change

UUUnknown User

1/10/2023

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⛄⛄Snowberb⛄

1/10/2023

wdym?

⛄⛄Snowberb⛄

1/10/2023

I just don't know how I can program that if:

data.length === 202 & limit === 10 -> 8
data.length === 56 & limit === 10 -> 4
data.length === 5 & limit === 15 -> 10

EEnfield-Li

1/10/2023

use &&

EEnfield-Li

1/10/2023

if(data.length === 202 && limit === 10) {
  return 8;
}

UUUnknown User

1/10/2023

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⛄⛄Snowberb⛄

1/10/2023

please read again the question, that's not dynamically thats hardcoding

⛄⛄Snowberb⛄

1/10/2023

yes there's logic behind, like obviosuly I dont need it hardcoded, both the length of data and limit can change, without me knowing what their value will be

UUUnknown User

1/10/2023

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⛄⛄Snowberb⛄

1/10/2023

lol I thought I had said it on the question, apologies. So if the limit is 10 and the data length is 17, 3 comes out of doing 10 - 7, as there's 10 items listed on each page

⛄⛄Snowberb⛄

1/10/2023

data.length === 202 and limit === 10 -> Last page only has 2 items on it, so the difference is 8

UUUnknown User

1/11/2023

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