Script – 22-55 Feb 1

SScript

2/1/2022

I'm trying to run the function till b.length === 1 and then return b What am I doing wrong? it returns undefined

function superDigit(n, k) {
  if (k === 1) return n;

  n = n.toString();
  let b = 0;
  for (let i = 0; i < k; i++) {
    n = n.concat(n);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(bb) {
    bb = bb.toString();
    bbb = 0;
    for (let i in bb) {
      bbb += parseInt(bb[i]);
    }
    b = bbb;
    if (b.length === 1) {
      return b;
    }
  }

 recall(b);
}

function superDigit(n, k) {
  if (k === 1) return n;

  n = n.toString();
  let b = 0;
  for (let i = 0; i < k; i++) {
    n = n.concat(n);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(bb) {
    bb = bb.toString();
    bbb = 0;
    for (let i in bb) {
      bbb += parseInt(bb[i]);
    }
    b = bbb;
    if (b.length === 1) {
      return b;
    }
  }

 recall(b);
}

SScriptyChris

2/1/2022

because you don't return recall(b) call?

Gghardin137

2/1/2022

wow you could probably stand to name your variables a bit better 🙂

SScript

2/1/2022

function recall(bb) {
    bb = bb.toString();
    bbb = 0;
    for (let i in bb) {
      bbb += parseInt(bb[i]);
    }
    b = bbb;
    console.log("2", b);
    return b;
  }
  if (b.length === 1) {
    return b;
  } else return recall(b);

function recall(bb) {
    bb = bb.toString();
    bbb = 0;
    for (let i in bb) {
      bbb += parseInt(bb[i]);
    }
    b = bbb;
    console.log("2", b);
    return b;
  }
  if (b.length === 1) {
    return b;
  } else return recall(b);

SScriptyChris

2/1/2022

i meant this

SScript

2/1/2022

😂 I was just rushing and giving it similar var names I tried that but still got undefined

SScriptyChris

2/1/2022

is b.length === 1condition ever met?

SScript

2/1/2022

yes

SScriptyChris

2/1/2022

so recall at that case should return non-undefined b variable, because it surely is array/string with length property equal to 1

SScript

2/1/2022

I'll look at my code

SScriptyChris

2/1/2022

to be clear, you mean that superDigit returns undefined or recall? and are you sure that recursion ends sometime, not throws call stack exceeded error?

SS3BAS

2/1/2022

Return the last line return recall(b) @Script

SScript

2/1/2022

Okay so I am finally exceeding the call stack

function superDigit(n, k) {
  //   if (k === 1) return n;

  n = n.toString();
  let n2 = n;
  let b = 0;
  for (let i = 0; i < k - 1; i++) {
    n = n.concat(n2);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(newVal) {
    newVal = newVal.toString();
    point0 = 0;
    for (let i in newVal) {
      point0 += parseInt(newVal[i]);
    }
    b = point0;
    if (b.length == 1) {
      return b;
    } else {
      recall(b);
    }
  }

  return recall(b);
}

function superDigit(n, k) {
  //   if (k === 1) return n;

  n = n.toString();
  let n2 = n;
  let b = 0;
  for (let i = 0; i < k - 1; i++) {
    n = n.concat(n2);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(newVal) {
    newVal = newVal.toString();
    point0 = 0;
    for (let i in newVal) {
      point0 += parseInt(newVal[i]);
    }
    b = point0;
    if (b.length == 1) {
      return b;
    } else {
      recall(b);
    }
  }

  return recall(b);
}

How do I manage this

SS3BAS

2/1/2022

Yeah then your base condition is never being met

SScript

2/1/2022

It is actually b becomes 3 that's length of 1

SS3BAS

2/1/2022

If you would properly hit the base condition you wouldn’t exceed the call stack Are you calling length on a number? Does that give you the amount of digits?

SScript

2/1/2022

yes b is an integer

SS3BAS

2/1/2022

What does the length of 0 return 0.length

SScript

2/1/2022

SS3BAS

2/1/2022

And 3.length? I’m on phone so I can’t verify myself

UUUnknown User

2/1/2022

Message Not Public

SS3BAS

2/1/2022

Are you perhaps assuming that you can call length on a number without actually trying it out?

UUUnknown User

2/1/2022

Message Not Public

SS3BAS

2/1/2022

Yeah

SScript

2/1/2022

same thing invalid

SS3BAS

2/1/2022

So why are you calling length on a number 😛 Turn it to a string first

SScript

2/1/2022

my bad

SS3BAS

2/1/2022

Don’t just assume code will work like you expect it to, you need to test and confirm even the smallest things heh Yeah all good

SScript

2/1/2022

ayee still gettin undefined coolcry

function superDigit(n, k) {
  n = n.toString();
  let n2 = n;
  let b = 0;
  for (let i = 0; i < k - 1; i++) {
    n = n.concat(n2);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(newVal) {
    newVal = newVal.toString();
    point0 = 0;
    for (let i in newVal) {
      point0 += parseInt(newVal[i]);
    }
    b = point0;
    if (b.toString().length === 1) {
      return b;
    } else {
      recall(b);
    }
  }
  return recall(b);
}

function superDigit(n, k) {
  n = n.toString();
  let n2 = n;
  let b = 0;
  for (let i = 0; i < k - 1; i++) {
    n = n.concat(n2);
  }
  for (let i in n) {
    b += parseInt(n[i]);
  }

  function recall(newVal) {
    newVal = newVal.toString();
    point0 = 0;
    for (let i in newVal) {
      point0 += parseInt(newVal[i]);
    }
    b = point0;
    if (b.toString().length === 1) {
      return b;
    } else {
      recall(b);
    }
  }
  return recall(b);
}

wait am I supposed to return recall(b) in recall()? Because I did now and it worked

SS3BAS

2/1/2022

Yeah you are indeed Since it will evaluate to a number, but that number needs to be returned to the caller

UUUnknown User

2/2/2022

2 Messages Not Public

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Script – 22-55 Feb 1

Script – 22-55 Feb 1

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