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✅ – Pink Hat – 00-54 Feb 15
in this code
why does
When it should be printing
this.pattern = [
{
method: new Function(`console.log(1)`),
bulletDelay: 1000
} ,{
method: new Function(`console.log(2)`),
bulletDelay: 1000
} ,{
method: new Function(`console.log(3)`),
bulletDelay: 1000
}
]
for (this.i in this.pattern) {
setTimeout(()=>this.pattern[this.i].method(), function (i){
this.z = 0;
for (this.j = i-1; this.j >=0; this.j--) {
try {
this.z += this.pattern[this.j]?.bulletDelay
} catch (error) {
console.error(error)
} finally {
continue
}
}
console.log(i)
return this.z
}(this.i))
console.log(this.pattern[this.i])
}why does
this.pattern[2] get printed 3 times?> 0
> {bulletDelay: 1000, method: ƒ}
> 1
> {bulletDelay: 1000, method: ƒ}
> 2
> {bulletDelay: 1000, method: ƒ}
> undefined
> 3
> 3
> 3When it should be printing
> 0
> {bulletDelay: 1000, method: ƒ}
> 1
> {bulletDelay: 1000, method: ƒ}
> 2
> {bulletDelay: 1000, method: ƒ}
> undefined
> 1
> 2
> 3Try caching
this.j as a local variablecaching it?
Yes, similarly as you do with
i regarding this.ilike this?
for (this.i in this.pattern) {
setTimeout(()=>this.pattern[this.i].method(), function (i, j){
this.z = 0;
for (j >=0; j--) {
try {
this.z += this.pattern[j]?.bulletDelay
} catch (error) {
console.error(error)
} finally {
continue
}
}
console.log(i)
return this.z
}(this.i, 0))
console.log(this.pattern[this.i])
}}(this.i, 0)) -> }(this.i, this.j))nothing
still the same result
Can you add labels to
console.log so it's more readable, which log refers to what value?sure
console.log('i:', i)
console.log('this.pattern[this.i]:',this.pattern[this.i])And show output
Where's that "3" log coming from? Add it label too
the 3 is the label
it was originally this
then so I could run it in chrome
this.pattern = [
{
method: new Function(`console.log(1)`),
bulletDelay: 1000
} ,{
method: new Function(`console.log(2)`),
bulletDelay: 1000
} ,{
method: new Function(`console.log(3)`),
bulletDelay: 1000
}
]Its a result of
this.pattern[2] being run 3 timesI think it's happening because this.i is already fully changed before the setTimeout occurs
Can you add counters to
pattern too? this.pattern = [
{
method: new Function(`console.log(1)`),
bulletDelay: 1000 ,
counter: 1,
} ,{
method: new Function(`console.log(2)`),
bulletDelay: 1000,
counter: 2,
} ,{
method: new Function(`console.log(3)`),
bulletDelay: 1000,
counter: 3,
}
]Show the console output - i suppose each pattern will have
counter: 3Yes
You could await timeout call
in the for function?
for (this.i in this.pattern) {
await new Promise(resolve => setTimeout(()=>this.pattern[this.i].method(), function (i, j){
// stuff
// `return this.z` becomes
resolve(this.z)
}(this.i, 0))
console.log(this.pattern[this.i])
}would that work?
It should
ok. I'll try it
If this
for..in is inside a function, then you have to make it asyncIf it's in top-level scope, then your script should work as a module, otherwise
await won't work, and you have to .then() the promiseand inside the .then you would put what exactly?
because it seems the await doesnt have anything referencing it
Your
console.logok.
What do you mean?
nvm that
so
now it's worse
it doesnt even wait the time it needs to
No, you have to wrap
console.log inside a function, which you pass to .then().then(), same as setTimeout() or Promise() expects a function to be passed, which is then called insidehuh?
what do u mean by this
im confused as hell
Read example in the docs
Passing a function
.then((value) => console.log( /* stuff */ ))I want the promise to pass after a certain time.
if I do
then what does that do
if I do
new Promise(resolve).then(() => console.log(/* stuff */)then what does that do
What
resolve is there?I already wrote you example with promisified
setTimeout above..ok, try this - i think i misread your code (2:30am on my side)
await new Promise(
(resolve) => {
setTimeout(
() => {
this.pattern[this.i].method();
resolve();
},
function (i, j){
// stuff
return this.z;
}(this.i, 0)
)
}
)
console.log(this.pattern[this.i]) threw this error (after I fixed some of the syntax cus it was complaining
Lacking closing curly brace
Add
} thereAnd the
console.log('what') is incorrectly place thereJust copy-paste this ☝️
Works for me on dry-run
it works
👍
I found a piece of code that works (slightly waltered from yours)
this.pattern = [
{
method: new Function('console.log("Counter: 1")'),
bulletDelay: 1000
} ,{
method: new Function('console.log("Counter: 2")'),
bulletDelay: 1000
} ,{
method: new Function('console.log("Counter: 3")'),
bulletDelay: 1000
}
]
for (this.i in this.pattern) {
await new Promise(
(resolve) => {
setTimeout(
() => {
this.pattern[this.i].method();
resolve();
},
function (i, j){
// stuff
return this.z;
}(this.i, 0)
)
console.log(this.pattern[this.i])
});
}and now we can close this. thanks for the help @ScriptyChris
#thanks
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