✅ Writing a scuffed way to use an "assignment" (=) operator

Obviously, there's no such thing as an assignment operator. I'd like to find some way around that.
I have a class that looks something like this:

struct MyType<T> {
  public int AField;
  public T Value {
    get {
      // Stuff to do with AField
    }
    set {
      // Stuff to do with AField
    }
  }

  public Type<T>(int aField) {
    AField = aField;
  }
}

struct MyType<T> {
  public int AField;
  public T Value {
    get {
      // Stuff to do with AField
    }
    set {
      // Stuff to do with AField
    }
  }

  public Type<T>(int aField) {
    AField = aField;
  }
}

I'd like to be able to assign values to this:

MyType<float> myType = new(20);

// What I want:
myType = 30.5f;
// What I have to do at the moment:
myType.Value = 30.5f;

MyType<float> myType = new(20);

// What I want:
myType = 30.5f;
// What I have to do at the moment:
myType.Value = 30.5f;

Is there any hacky, bodged, whatever way of doing this? I can't do it like this, obviously, because operators are static:

public static implicit operator MyType<T>(T value) {
  MyType<T> ret = new(this.AField);
  ret.Value = value;
  return ret;
}

public static implicit operator MyType<T>(T value) {
  MyType<T> ret = new(this.AField);
  ret.Value = value;
  return ret;
}

Any ideas are appreciated, thanks!

C#•3y ago•

20 replies

NoSkillPureAndy

✅ Writing a scuffed way to use an "assignment" (=) operator

Obviously, there's no such thing as an assignment operator. I'd like to find some way around that.
I have a class that looks something like this:

struct MyType<T> {
  public int AField;
  public T Value {
    get {
      // Stuff to do with AField
    }
    set {
      // Stuff to do with AField
    }
  }

  public Type<T>(int aField) {
    AField = aField;
  }
}

struct MyType<T> {
  public int AField;
  public T Value {
    get {
      // Stuff to do with AField
    }
    set {
      // Stuff to do with AField
    }
  }

  public Type<T>(int aField) {
    AField = aField;
  }
}

I'd like to be able to assign values to this:

MyType<float> myType = new(20);

// What I want:
myType = 30.5f;
// What I have to do at the moment:
myType.Value = 30.5f;

MyType<float> myType = new(20);

// What I want:
myType = 30.5f;
// What I have to do at the moment:
myType.Value = 30.5f;

Is there any hacky, bodged, whatever way of doing this? I can't do it like this, obviously, because operators are static:

public static implicit operator MyType<T>(T value) {
  MyType<T> ret = new(this.AField);
  ret.Value = value;
  return ret;
}

public static implicit operator MyType<T>(T value) {
  MyType<T> ret = new(this.AField);
  ret.Value = value;
  return ret;
}

Any ideas are appreciated, thanks!

✅ Writing a scuffed way to use an "assignment" (=) operator

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