❔ Need Help Understanding Casting

I have an equation that returns a float of value

0.6561f

0.6561f

. When i cast it to a double, it turns into

0.6560999751091003d

0.6560999751091003d

. I don't understand why.

Equation:

Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

Double:

(double)Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

(double)Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

int num = 1272

int num = 1272

Mathf.Pow(float f, float p)

Mathf.Pow(float f, float p)

returns

(float)Math.Pow((double)f, (double)p);

(float)Math.Pow((double)f, (double)p);

C#•3y ago•

95 replies

I have an equation that returns a float of value

0.6561f

0.6561f

. When i cast it to a double, it turns into

0.6560999751091003d

0.6560999751091003d

. I don't understand why.

Equation:

Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

Double:

(double)Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

(double)Mathf.Pow(Math.Max((float)num - 300f, 0f) / 1200f, 2f

int num = 1272

int num = 1272

Mathf.Pow(float f, float p)

Mathf.Pow(float f, float p)

returns

(float)Math.Pow((double)f, (double)p);

(float)Math.Pow((double)f, (double)p);