How to implement the following simple comparison function

I would like to implement the following simple function, but I cannot find an alternative for AnyType (interface?) that defines comparison operators. In the following code a

__ne__

__ne__

is needed for

ai != bi

ai != bi

.

It's as if I'm missing a manual. If someone knows how to do this, or knows how to make me cope that is cannot be done...

fn equal_vector[T: AnyType](a: DynamicVector[T], b: DynamicVector[T]) -> Bool:
    # assumed a and b are sorted
    if a.__len__() != b.__len__():
        return False
    for i in range (a.__len__()):
        let ai: T = a.__getitem__(i)
        let bi: T = b.__getitem__(i)
        if ai != bi:  ## compilation error HERE
            return False
    return True

fn equal_vector[T: AnyType](a: DynamicVector[T], b: DynamicVector[T]) -> Bool:
    # assumed a and b are sorted
    if a.__len__() != b.__len__():
        return False
    for i in range (a.__len__()):
        let ai: T = a.__getitem__(i)
        let bi: T = b.__getitem__(i)
        if ai != bi:  ## compilation error HERE
            return False
    return True

Modular•3y ago•

2 replies

Henk-Jan Lebbink

How to implement the following simple comparison function

I would like to implement the following simple function, but I cannot find an alternative for AnyType (interface?) that defines comparison operators. In the following code a

__ne__

__ne__

is needed for

ai != bi

ai != bi

.

It's as if I'm missing a manual. If someone knows how to do this, or knows how to make me cope that is cannot be done...

fn equal_vector[T: AnyType](a: DynamicVector[T], b: DynamicVector[T]) -> Bool:
    # assumed a and b are sorted
    if a.__len__() != b.__len__():
        return False
    for i in range (a.__len__()):
        let ai: T = a.__getitem__(i)
        let bi: T = b.__getitem__(i)
        if ai != bi:  ## compilation error HERE
            return False
    return True

fn equal_vector[T: AnyType](a: DynamicVector[T], b: DynamicVector[T]) -> Bool:
    # assumed a and b are sorted
    if a.__len__() != b.__len__():
        return False
    for i in range (a.__len__()):
        let ai: T = a.__getitem__(i)
        let bi: T = b.__getitem__(i)
        if ai != bi:  ## compilation error HERE
            return False
    return True

How to implement the following simple comparison function

Similar Threads

How to implement the following simple comparison function

Similar Threads

Similar Threads

Similar Threads