4 replies

Conditionally updating a variable with choose()

How do I create and update a variable with a conditional? I need a number to be calculated based on an arrangement of requirements. Here is a very simplified example of what I was trying to do:

g.addV('App').property('name', 'A').property('requirement1', true).property('requirement2', true).
addV('App').property('name', 'B').property('requirement1', true).property('requirement2', false).
addV('App').property('name', 'C').property('requirement1', false).property('requirement2', false).property('requirement3', true)

g.V().
    project('id', 'name', 'requirement1', 'requirement2', 'value').
    by('id').
    by('name').
    by('requirement1').
    by('requirement2').
    by(
        map{
            total = 0;
            choose(
                and(
                    has('requirement1', true),
                    has('requirement2', true)),
                constant(total + 1),
                identity()
            )
            choose(
                has('requirement3', true),
                constant(total + 1),
                identity()
            )
            total
        }
    )

g.addV('App').property('name', 'A').property('requirement1', true).property('requirement2', true).
addV('App').property('name', 'B').property('requirement1', true).property('requirement2', false).
addV('App').property('name', 'C').property('requirement1', false).property('requirement2', false).property('requirement3', true)

g.V().
    project('id', 'name', 'requirement1', 'requirement2', 'value').
    by('id').
    by('name').
    by('requirement1').
    by('requirement2').
    by(
        map{
            total = 0;
            choose(
                and(
                    has('requirement1', true),
                    has('requirement2', true)),
                constant(total + 1),
                identity()
            )
            choose(
                has('requirement3', true),
                constant(total + 1),
                identity()
            )
            total
        }
    )

I ultimately found a solution, but I ended up having to create different conditionals for every possible combination. It is repetitive and hard to read. Is there a way to do this, that is similar to what I shared above? Thank you!

Solution

sorry, but it looks like this question was missed last week somehow. i think you're mostly on track for the best way to do this by using

choose()

choose()

. you could simplify your syntax a fair bit i think by using

sack()

sack()

gremlin> g.withSack(0).V().
......1>   project('id', 'name', 'requirement1', 'requirement2', 'requirement3', 'value').
......2>     by('id').
......3>     by('name').
......4>     by('requirement1').
......5>     by('requirement2').
......6>     by('requirement3').
......7>     by(choose(has('requirement1', true).has('requirement2', true), sack(sum).by(constant(1))).
......8>        choose(has('requirement3', true), sack(sum).by(constant(1))).
......9>        sack())
==>[name:A,requirement1:true,requirement2:true,value:1]
==>[name:B,requirement1:true,requirement2:false,value:0]
==>[name:C,requirement1:false,requirement2:false,requirement3:true,value:1]

gremlin> g.withSack(0).V().
......1>   project('id', 'name', 'requirement1', 'requirement2', 'requirement3', 'value').
......2>     by('id').
......3>     by('name').
......4>     by('requirement1').
......5>     by('requirement2').
......6>     by('requirement3').
......7>     by(choose(has('requirement1', true).has('requirement2', true), sack(sum).by(constant(1))).
......8>        choose(has('requirement3', true), sack(sum).by(constant(1))).
......9>        sack())
==>[name:A,requirement1:true,requirement2:true,value:1]
==>[name:B,requirement1:true,requirement2:false,value:0]
==>[name:C,requirement1:false,requirement2:false,requirement3:true,value:1]

I'm not sure how complex your conditionals will end up being but with some proper indentation i think it can stay readable.

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Apache TinkerPop•2y ago•

4 replies

Katlin

Conditionally updating a variable with choose()

How do I create and update a variable with a conditional? I need a number to be calculated based on an arrangement of requirements. Here is a very simplified example of what I was trying to do:

g.addV('App').property('name', 'A').property('requirement1', true).property('requirement2', true).
addV('App').property('name', 'B').property('requirement1', true).property('requirement2', false).
addV('App').property('name', 'C').property('requirement1', false).property('requirement2', false).property('requirement3', true)

g.V().
    project('id', 'name', 'requirement1', 'requirement2', 'value').
    by('id').
    by('name').
    by('requirement1').
    by('requirement2').
    by(
        map{
            total = 0;
            choose(
                and(
                    has('requirement1', true),
                    has('requirement2', true)),
                constant(total + 1),
                identity()
            )
            choose(
                has('requirement3', true),
                constant(total + 1),
                identity()
            )
            total
        }
    )

g.addV('App').property('name', 'A').property('requirement1', true).property('requirement2', true).
addV('App').property('name', 'B').property('requirement1', true).property('requirement2', false).
addV('App').property('name', 'C').property('requirement1', false).property('requirement2', false).property('requirement3', true)

g.V().
    project('id', 'name', 'requirement1', 'requirement2', 'value').
    by('id').
    by('name').
    by('requirement1').
    by('requirement2').
    by(
        map{
            total = 0;
            choose(
                and(
                    has('requirement1', true),
                    has('requirement2', true)),
                constant(total + 1),
                identity()
            )
            choose(
                has('requirement3', true),
                constant(total + 1),
                identity()
            )
            total
        }
    )

Solution

sorry, but it looks like this question was missed last week somehow. i think you're mostly on track for the best way to do this by using

choose()

choose()

. you could simplify your syntax a fair bit i think by using

sack()

sack()

gremlin> g.withSack(0).V().
......1>   project('id', 'name', 'requirement1', 'requirement2', 'requirement3', 'value').
......2>     by('id').
......3>     by('name').
......4>     by('requirement1').
......5>     by('requirement2').
......6>     by('requirement3').
......7>     by(choose(has('requirement1', true).has('requirement2', true), sack(sum).by(constant(1))).
......8>        choose(has('requirement3', true), sack(sum).by(constant(1))).
......9>        sack())
==>[name:A,requirement1:true,requirement2:true,value:1]
==>[name:B,requirement1:true,requirement2:false,value:0]
==>[name:C,requirement1:false,requirement2:false,requirement3:true,value:1]

gremlin> g.withSack(0).V().
......1>   project('id', 'name', 'requirement1', 'requirement2', 'requirement3', 'value').
......2>     by('id').
......3>     by('name').
......4>     by('requirement1').
......5>     by('requirement2').
......6>     by('requirement3').
......7>     by(choose(has('requirement1', true).has('requirement2', true), sack(sum).by(constant(1))).
......8>        choose(has('requirement3', true), sack(sum).by(constant(1))).
......9>        sack())
==>[name:A,requirement1:true,requirement2:true,value:1]
==>[name:B,requirement1:true,requirement2:false,value:0]
==>[name:C,requirement1:false,requirement2:false,requirement3:true,value:1]

I'm not sure how complex your conditionals will end up being but with some proper indentation i think it can stay readable.

Jump to solution

Conditionally updating a variable with choose()

Conditionally updating a variable with choose()

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