C#•2y ago

✅ how can i let an interface implement a function of a super-interface, instead of shadowing it?

LastExceed · 2024-05-02T10:15:38.191Z

```csharp public class MyClass : IOne; public interface IOne : ITwo { public void Foo() { Console.WriteLine(); } } public interface ITwo { public void Foo(); } ``` this doesnt compile, because `IOne.Foo` is considered a separate function that shadows `ITwo.Foo`. how do i tell `IOne` to provide a default implementation for `ITwo.Foo` instead of shadowing it?

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

public class MyClass : IOne;

public interface IOne : ITwo
{
    public void Foo()
    {
        Console.WriteLine();
    }
}

public interface ITwo
{
    public void Foo();
}

this doesnt compile, because

IOne.Foo

IOne.Foo

IOne.Foo

IOne.Foo is considered a separate function that shadows

ITwo.Foo

ITwo.Foo

ITwo.Foo

ITwo.Foo. how do i tell

IOne

IOne

IOne

IOne to provide a default implementation for

ITwo.Foo

ITwo.Foo

ITwo.Foo

ITwo.Foo instead of shadowing it?

✅ how can i let an interface implement a function of a super-interface, instead of shadowing it?

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