Drizzle TeamDT
Drizzle Team•17mo ago
modii

drizzle-zod createInsertSchema gives optional types

I have the following table:

export const Recipe = pgTable("recipe", {
  id: uuid("id").notNull().primaryKey().defaultRandom(),
  title: varchar("title", { length: 256 }).notNull(),
  description: text("description").notNull(),
  mainImage: varchar("main_image", { length: 512 }),
  ingredientNames: varchar("ingredient_names", { length: 255 }).array().notNull(), // Array of ingredient names
  ingredientQuantities: real("ingredient_quantities").array().notNull(), // Array of ingredient quantities
  ingredientUnits: varchar("ingredient_units", { length: 20 }).array().notNull(), // Array of ingredient units
  stepDescriptions: text("step_descriptions").array().notNull(), // Array of step descriptions
  stepImages: varchar("step_images", { length: 512 }).array().notNull(), // Array of step images
  createdAt: timestamp("created_at").defaultNow().notNull(),
  updatedAt: timestamp("updated_at", {
    mode: "date",
    withTimezone: true,
  }).$onUpdateFn(() => sql`now()`),
  postedBy: uuid("posted_by").references(() => User.id, { onDelete: "cascade" }),
});


And I am using drizzle-zod to generate a Zod type from my schema:
export const CreateRecipeSchema = createInsertSchema(Recipe).omit({
  id: true,
  createdAt: true,
  updatedAt: true,
});


However when I try to use the type within my tRPC procedure as such, I get a typescript error, which seems to be complaining that the properties within CreateRecipeSchema are optional:

  create: publicProcedure
  .input(CreateRecipeSchema)
  .mutation(async ({ input, ctx }) => {
    const newRecipe = await ctx.db.insert(Recipe).values(input);

    return newRecipe;
  }),


I'm quite new to drizzle and zod, and from what I gather from documentation, I am using zod correctly, but I am not sure.
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