Working with the result of db.execute() (mysql2)

(TypeScript newbie here.)
In my (SvelteKit) application I want to (health) check if certain database tables exist when the user visits the main page.
What I tried:

    const [ rows, fields] = await db.execute(
        sql`SELECT table_name FROM information_schema.tables;`)

    return {
        tables: rows.map((x) => x.table_name).filter((x) => x.startsWith('virtual_'))
    };

    const [ rows, fields] = await db.execute(
        sql`SELECT table_name FROM information_schema.tables;`)

    return {
        tables: rows.map((x) => x.table_name).filter((x) => x.startsWith('virtual_'))
    };

    const [ rows, fields] = await db.execute(
        sql`SELECT table_name FROM information_schema.tables;`)

    return {
        tables: rows.map((x) => x.table_name).filter((x) => x.startsWith('virtual_'))
    };

    const [ rows, fields] = await db.execute(
        sql`SELECT table_name FROM information_schema.tables;`)

    return {
        tables: rows.map((x) => x.table_name).filter((x) => x.startsWith('virtual_'))
    };

But my rows.map() seems wrong. I get "Property 'map' does not exist on type 'ResultSetHeader'.".
How would I properly work with the "rows" object?

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Working with the result of db.execute() (mysql2)

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