How would you define an object with optional keys, but require at least one of the keys to be filled

An example of a very basic schema:

const schema = type({ a: type.string.optional(), b: type.string.optional() });

const schema = type({ a: type.string.optional(), b: type.string.optional() });

I'd like this to accept values

{a: 'foo'}

{a: 'foo'}

{ b: 'foo' }

{ b: 'foo' }

, and

{ a: 'foo', b: 'bar' }

{ a: 'foo', b: 'bar' }

, but fail on

{}

{}

. It would be a lovely bonus for the type to be inferred as

{ a: string, b?: string } | { a?: string, b: string }

{ a: string, b?: string } | { a?: string, b: string }

as well. Is there a way to do this without explicitly specifying that inferred type as an arktype union using

.or

.or

arktype•2y ago•

15 replies