Extract routes from hono definition

Hi everyone, i want to extract all the routes from hono definition for example :

export const app = new Hono<Env>()
  .route('/transactions', transactionsRoute);

export const app = new Hono<Env>()
  .route('/transactions', transactionsRoute);

How is it possible ?
I want to make a function that take a typesafe parameter that will be the route

const fn = (route: AnyPossibleRoute) => {}

const fn = (route: AnyPossibleRoute) => {}

and when i call the function fn, there will be autocompletion and i can have these possible options :

/api/transactions

/api/transactions

/api/transactions/all

/api/transactions/all

/api/transactions/:id

/api/transactions/:id

etc ...

I'm fighting with

ExtractSchema

ExtractSchema

utility type but I don't achive my goal
Thanks.

Hono•13mo ago•

7 replies

Hi everyone, i want to extract all the routes from hono definition for example :

export const app = new Hono<Env>()
  .route('/transactions', transactionsRoute);

export const app = new Hono<Env>()
  .route('/transactions', transactionsRoute);

How is it possible ?
I want to make a function that take a typesafe parameter that will be the route

const fn = (route: AnyPossibleRoute) => {}

const fn = (route: AnyPossibleRoute) => {}

and when i call the function fn, there will be autocompletion and i can have these possible options :

/api/transactions

/api/transactions

/api/transactions/all

/api/transactions/all

/api/transactions/:id

/api/transactions/:id

etc ...

I'm fighting with

ExtractSchema

ExtractSchema

utility type but I don't achive my goal
Thanks.