T
TanStack•7mo ago
rare-sapphire

Why Route.useSearch returns any here?

Hello, This is probably a stupid question, but I can't find my mistake. In this route: 
import { createFileRoute } from "@tanstack/react-router";
import { z } from "zod";

export const Route = createFileRoute("/toto")({
  validateSearch: () => ({
    myparam: z.string().default("mydefaultvalue"),
  }),
  component: RouteComponent,
});

function RouteComponent() {
  const data = Route.useSearch();
  console.log(">>", data);
  return <div>Hello "/toto"!</div>;
}
import { createFileRoute } from "@tanstack/react-router";
import { z } from "zod";

export const Route = createFileRoute("/toto")({
  validateSearch: () => ({
    myparam: z.string().default("mydefaultvalue"),
  }),
  component: RouteComponent,
});

function RouteComponent() {
  const data = Route.useSearch();
  console.log(">>", data);
  return <div>Hello "/toto"!</div>;
}
data is of type any. What am I missing?
4 Replies
future-harlequin
future-harlequin•7mo ago
your validator should be a z.object({ myparam: z.string().default("...")})
rare-sapphire
rare-sapphireOP•7mo ago
hm what's the difference between @tanstack/router-zod-adapter and @tanstack/zod-adapter? I realised this example was wrong and I should have used your solution instead of a callback, but it didn't solve my issue
future-harlequin
future-harlequin•7mo ago
we renamed to the one without the router prefix so use that
rare-sapphire
rare-sapphireOP•7mo ago
ok thank you!

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