Json Serializing And Deserializing Practice Errors

using System.Collections.Generic;
using System.Text.Json;
using System.Text.Json.Serialization;

namespace Cookie_Cookbook.Recipe.Ingredient
{
    public static class IngredientManagement
    {
        public static void ShowCurrentRecipes(List<Ingredient> list)
        {
            if (list.Count == 0)
            {
                Console.WriteLine("There is no recipes added.");
            }
            else
            {
                Console.WriteLine("Recipe Added: ");
                foreach (Ingredient recipe in list)
                {
                    Console.WriteLine($"{recipe.Name}:{recipe.Instructions}");
                }
            }
        }
        public static void ShowIngredients()
        {
            Console.WriteLine("1. Wheat flour\n2. Coconut flour\n3. Butter\n4. Chocolate\n5. Sugar\n6. Cardamom\n7. Cinnamon\n8. Cocoa powder");
        }
        private static readonly string filePath = "recipe.json";
        public static void Save(List<Ingredient> list)
        {
            string toJson = JsonSerializer.Serialize(list);
            File.WriteAllText(filePath, toJson);
        }
        public static List<Ingredient> Load()
        {
            if (File.Exists(filePath))
            {
                string jsonData = File.ReadAllText(filePath);
                return JsonSerializer.Deserialize<List<Ingredient>>(jsonData) ?? new List<Ingredient>();
            }
            return new List<Ingredient>();
        }


    }
}

System.NotSupportedException: 'Deserialization of types without a parameterless constructor, a singular parameterized constructor, or a parameterized constructor annotated with 'JsonConstructorAttribute' is not supported. Type 'Cookie_Cookbook.Recipe.Ingredient.Ingredient'. Path: $[0] | LineNumber: 0 | BytePositionInLine: 2.'