Inject multiple implementations of the same interface

what's the proper way to inject multiple implementations of the same interface?

public class FooBar{
     public FooBar(IInterface something){

     }
}
builder.Services.AddScoped<IInterface, Implementation1>();
builder.Services.AddScoped<IInterface, Implementation2>();

public class FooBar{
     public FooBar(IInterface something){

     }
}
builder.Services.AddScoped<IInterface, Implementation1>();
builder.Services.AddScoped<IInterface, Implementation2>();

is a setup like this possible? Which one is being injected? How to have different classes use different impelmentations without them using concrete dependencies of Implementation1 and Implementation2?

C#•4mo ago•

6 replies

Thalnos

Inject multiple implementations of the same interface

what's the proper way to inject multiple implementations of the same interface?

public class FooBar{
     public FooBar(IInterface something){

     }
}
builder.Services.AddScoped<IInterface, Implementation1>();
builder.Services.AddScoped<IInterface, Implementation2>();

public class FooBar{
     public FooBar(IInterface something){

     }
}
builder.Services.AddScoped<IInterface, Implementation1>();
builder.Services.AddScoped<IInterface, Implementation2>();

Inject multiple implementations of the same interface

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