Theo's Typesafe Cult•3y ago

Single element type of inferred router output array type

I'm trying to type a single object from an array but I don't want to manually create it. I've been using inferRouterOutputs so I was wondering if it's possible to remove the [] from the type so that it is just an object.

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

With AlItemsOutput being:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

But I would like to convert it to:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

5 Replies

erik.gh•3y ago

What about something like this:

type ArrayItem<T extends any[]> = T extends (infer I)[] ? I  : never;

type ArrayItem<T extends any[]> = T extends (infer I)[] ? I  : never;

jix74OP•3y ago

@erik.gh works! Thanks so much man!

erik.gh•3y ago

great!

Unknown User•3y ago

Message Not Public

erik.gh•3y ago

that's way cooler I did not know that

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Single element type of inferred router output array type

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