5 replies

Single element type of inferred router output array type

I'm trying to type a single object from an array but I don't want to manually create it.
I've been using inferRouterOutputs so I was wondering if it's possible to remove the [] from the type so that it is just an object.

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

With AlItemsOutput being:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

But I would like to convert it to:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

TTC

Theo's Typesafe Cult•4y ago•

5 replies

jix74

Single element type of inferred router output array type

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

type RouterOutput = inferRouterOutputs<AppRouter>;
type AllItemsOutput = RouterOutput["items"]["getAllItems"];

With AlItemsOutput being:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
}[] | undefined

But I would like to convert it to:

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

type AllItemsOutput = {
    name: string | null;
    id: string;
    description: string | null;
} | undefined

Single element type of inferred router output array type

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