C#•3y ago

✅ Make method implemented in interface accessible from implementing type

i have an interface

interface ICL
{
  public IEnumerable<ICLPlatform> GetPlatforms()
  {
    // code
  }
}

interface ICL
{
  public IEnumerable<ICLPlatform> GetPlatforms()
  {
    // code
  }
}

interface ICL
{
  public IEnumerable<ICLPlatform> GetPlatforms()
  {
    // code
  }
}

interface ICL
{
  public IEnumerable<ICLPlatform> GetPlatforms()
  {
    // code
  }
}

and an implementing struct

struct CLAdapter : ICL
{
}

struct CLAdapter : ICL
{
}

struct CLAdapter : ICL
{
}

struct CLAdapter : ICL
{
}

now

GetPlatforms()

GetPlatforms()

GetPlatforms()

GetPlatforms() isnt reachable via

new CLAdapter().GetPlatforms()

new CLAdapter().GetPlatforms()

new CLAdapter().GetPlatforms()

new CLAdapter().GetPlatforms(), how can i make that accessible?

i tried implementing it in the adapter by simply casting

this

this

this

this to

ICL

ICL

ICL

ICL, but then i run into stack overflows

    /// <inheritdoc/>
    public IEnumerable<ICLPlatform> GetPlatforms()
    {
        return ((ICL)this).GetPlatforms();
    }

    /// <inheritdoc/>
    public IEnumerable<ICLPlatform> GetPlatforms()
    {
        return ((ICL)this).GetPlatforms();
    }

    /// <inheritdoc/>
    public IEnumerable<ICLPlatform> GetPlatforms()
    {
        return ((ICL)this).GetPlatforms();
    }

    /// <inheritdoc/>
    public IEnumerable<ICLPlatform> GetPlatforms()
    {
        return ((ICL)this).GetPlatforms();
    }