Arduino•3y ago

Motor CC turning (Project 9)

Hello, I bought the starter kit of Arduino (the kit with the book which has 15 projects) and I tried to do the 9th but my motor is still turning when I am pressing my button, I did a simulation ; Code:

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
}

void loop() {
  switchState = digitalRead(switchPin);

  Serial.println(switchState);

  if (switchState = HIGH) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
}

void loop() {
  switchState = digitalRead(switchPin);

  Serial.println(switchState);

  if (switchState = HIGH) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

28 Replies

Unknown User•3y ago

Message Not Public

ProgramOP•3y ago

And on B what I do then? On the book it's like this so what I have to change with my transistor. My transistor is mosfet in my kit.

Unknown User•3y ago

Message Not Public

AnonEngineering•3y ago

it gets clearer, if it's an N channel MOSFET the pinout is likely Gate Drain Source... but the sim won't know that...

Unknown User•3y ago

Message Not Public

ProgramOP•3y ago

I have this one.

ProgramOP•3y ago

@Deleted User

Unknown User•3y ago

Message Not Public

ProgramOP•3y ago

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
}

void loop() {
  switchState = digitalRead(switchPin);

  Serial.println(switchState);

  if (switchState = HIGH) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
}

void loop() {
  switchState = digitalRead(switchPin);

  Serial.println(switchState);

  if (switchState = HIGH) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

9 -> to the first born of the transistor (first img). 2 -> the button.

ProgramOP•3y ago

@Deleted User :>. No idea?

ProgramOP•3y ago

I have the same circuit :

ProgramOP•3y ago

But it does not, the motor is not stopping when I pressed or not on the button. But I have info about the button so it works. But just the motor is not listening.

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState = HIGH) {
    Serial.println(digitalRead(motorPin));
    digitalWrite(motorPin, HIGH);
    Serial.println(digitalRead(motorPin));
  } else {
    Serial.println(digitalRead(motorPin));
    digitalWrite(motorPin, LOW);
    Serial.println(digitalRead(motorPin));
  }
}

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, OUTPUT);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState = HIGH) {
    Serial.println(digitalRead(motorPin));
    digitalWrite(motorPin, HIGH);
    Serial.println(digitalRead(motorPin));
  } else {
    Serial.println(digitalRead(motorPin));
    digitalWrite(motorPin, LOW);
    Serial.println(digitalRead(motorPin));
  }
}

I have always "1".

AnonEngineering•3y ago

the switchPin is an INPUT

ProgramOP•3y ago

Did not fix :(. @AnonEngineering

AnonEngineering•3y ago

need a lot more detail, how is the switch wired, for one and what is driving the motor, a transistor hopefully?

ProgramOP•3y ago

Yes? Look at the circuit?

Unknown User•3y ago

Message Not Public

ProgramOP•3y ago

No, but there you have to stop making fun of the world. If you are not able to look at a circuit, there is a problem, EVERYTHING IS ON IT, I GAVE EVERYTHING.

AnonEngineering•3y ago

what is this? (it's part number) https://media.discordapp.net/attachments/1112516980864454716/1113024592102035506/IMG_20230530_103117.jpg?width=266&height=473 inside an if you need to compare == not set = here is an example of what you are trying to do https://www.tinkercad.com/things/g5OKJ6mUJRG-basic-dc-motor-driver/editel

ProgramOP•3y ago

Wtf??? Why it's not "=="... Mb I will try.

AnonEngineering•3y ago

== compares two values, = sets a value to be equal to

ProgramOP•3y ago

Idk why I did not set "=="... Thanks. SO MUCH. I tought it was a problem about my motor :(. Now one thing :

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

int enableMotor;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, INPUT);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState == HIGH) {
    enableMotor = 1;
  } else {
    enableMotor = 0;
  }

  Serial.println(enableMotor);

  if (enableMotor == 1) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;

int enableMotor;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, INPUT);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState == HIGH) {
    enableMotor = 1;
  } else {
    enableMotor = 0;
  }

  Serial.println(enableMotor);

  if (enableMotor == 1) {
    digitalWrite(motorPin, HIGH);
  } else {
    digitalWrite(motorPin, LOW);
  }
}

I would like to do not have to press always on the button. Once I press -> motor turn until I press. If I press again it stops the motor. But I tried this, it does not work.

AnonEngineering•3y ago

look at the StateChangeDetect example any progress?

ProgramOP•3y ago

I did not understand...

AnonEngineering•3y ago

here's an example https://www.tinkercad.com/things/g5OKJ6mUJRG-basic-dc-motor-driver/editel

ProgramOP•3y ago

Ah thanks.

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;
int motorState = 0;
int oldSwitchState = 1;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, INPUT_PULLUP);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState != oldSwitchState)    {
      if (switchState == LOW) { 
        Serial.println("Switch was pressed");
        motorState = !motorState;
          Serial.print("Motor state is ");
          Serial.println(motorState? "true" : "false");
      } else {
        Serial.println("Switch was released\n");
      }
    delay(20);
  }
  oldSwitchState = switchState;
  
  digitalWrite(motorPin, motorState);
}

c++
const int switchPin = 2;
const int motorPin = 9;
int switchState = 0;
int motorState = 0;
int oldSwitchState = 1;

void setup() {
  Serial.begin(9600);
  pinMode(switchPin, INPUT_PULLUP);
  pinMode(motorPin, OUTPUT);
  digitalWrite(motorPin, LOW);
}

void loop() {
  switchState = digitalRead(switchPin);
  if (switchState != oldSwitchState)    {
      if (switchState == LOW) { 
        Serial.println("Switch was pressed");
        motorState = !motorState;
          Serial.print("Motor state is ");
          Serial.println(motorState? "true" : "false");
      } else {
        Serial.println("Switch was released\n");
      }
    delay(20);
  }
  oldSwitchState = switchState;
  
  digitalWrite(motorPin, motorState);
}

Alright I will study this.

AnonEngineering•3y ago

feel free to ask if you get stuck

Gaming

Programming

Motor CC turning (Project 9)

Did you find this page helpful?