6 replies

Piping in Bash (`echo "blah" | foo`)

In bash we can use the pipe character to pass some content to a command;

echo "blah" | foo

echo "blah" | foo

If I'm the author of the command

foo

foo

, how can I access that content. eg

"blah"

"blah"

?

As I understand it,

"blah"

"blah"

should be the stdin for

foo

foo

, however when I write the following implementation I get no result;

function foo() { # I like brackets, sue me
  echo "$@"
}

function foo() { # I like brackets, sue me
  echo "$@"
}

Though running

foo "blah"

foo "blah"

works as expected. I'm guessing

$@

$@

is not the correct symbol to use for this