8 replies

Transforming `S.record(S.string, S.unknown)` to `S.struct({ a: S.string })` using `S.transform`

Is it possible to go from

S.record(S.string, S.unknown)

S.record(S.string, S.unknown)

S.struct({ a: S.string })

S.struct({ a: S.string })

other than:

S.transform(
  S.record(S.string, S.unknown),
  S.struct({ a: S.string }),
  (a) => a as { a: string },
  identity,
)

S.transform(
  S.record(S.string, S.unknown),
  S.struct({ a: S.string }),
  (a) => a as { a: string },
  identity,
)

S.record(S.string, S.unknown).pipe(S.compose(S.struct({ a: S.string })))

S.record(S.string, S.unknown).pipe(S.compose(S.struct({ a: S.string })))

would be ideal but it doesn't type check.

8 replies

Is it possible to go from

S.record(S.string, S.unknown)

S.record(S.string, S.unknown)

S.struct({ a: S.string })

S.struct({ a: S.string })

other than:

S.transform(
  S.record(S.string, S.unknown),
  S.struct({ a: S.string }),
  (a) => a as { a: string },
  identity,
)

S.transform(
  S.record(S.string, S.unknown),
  S.struct({ a: S.string }),
  (a) => a as { a: string },
  identity,
)

S.record(S.string, S.unknown).pipe(S.compose(S.struct({ a: S.string })))

S.record(S.string, S.unknown).pipe(S.compose(S.struct({ a: S.string })))

would be ideal but it doesn't type check.