5 replies

Partitioning a Chunk into Chunks of B and C

Jules · 2023-08-02T12:30:06.459Z

Hi 🙂 I have a function `const bOrC: (a: A) => B | C` and a `Chunk `, is there a `partition` function to get back a `[Chunk , Chunk ]`? Something like: ```ts const bOrC: (a: A) => B | C = (a: A) => ... const as: Chunk = ... const [bs, cs] = Chunk.partition(as, bOrC) ```

I have a function

const bOrC: (a: A) => B | C

const bOrC: (a: A) => B | C

const bOrC: (a: A) => B | C

const bOrC: (a: A) => B | C and a

Chunk<A>

Chunk<A>

Chunk<A>

Chunk<A>, is there a

partition

partition

partition

partition function to get back a

[Chunk<B>, Chunk<C>]

[Chunk<B>, Chunk<C>]

[Chunk<B>, Chunk<C>]

[Chunk<B>, Chunk<C>]?
Something like:

const bOrC: (a: A) => B | C = (a: A) => ...
const as: Chunk<A> = ...

const [bs, cs] = Chunk.partition(as, bOrC)

const bOrC: (a: A) => B | C = (a: A) => ...
const as: Chunk<A> = ...

const [bs, cs] = Chunk.partition(as, bOrC)

const bOrC: (a: A) => B | C = (a: A) => ...
const as: Chunk<A> = ...

const [bs, cs] = Chunk.partition(as, bOrC)

const bOrC: (a: A) => B | C = (a: A) => ...
const as: Chunk<A> = ...

const [bs, cs] = Chunk.partition(as, bOrC)

Partitioning a Chunk into Chunks of B and C

Similar Threads

Similar Threads

Similar Threads