❔ Generics

I want to start off by saying I have no clue what I'm talking about. With that out of the way I have a generic function that I want pass a type into, but I want to store that type in a variable and let it be subject to change. Below is an example in a console application which definitively doesn't work, but it demonstrates how I would want it to work.

Random randomClass = new Random();
List<Type> aList = new List<Type> { new A(), new B(), new C() };
int randomInteger = randomClass.Next(3);
Type type = aList[randomInteger];
typeFunc<type>();
static void typeFunc<T>() where T : A
{
    Console.WriteLine("This worked");
}

public class A
{
    
}
public class B : A
{

}
public class C : A
{

}

Random randomClass = new Random();
List<Type> aList = new List<Type> { new A(), new B(), new C() };
int randomInteger = randomClass.Next(3);
Type type = aList[randomInteger];
typeFunc<type>();
static void typeFunc<T>() where T : A
{
    Console.WriteLine("This worked");
}

public class A
{
    
}
public class B : A
{

}
public class C : A
{

}

How is this done? Thanks

C#•3y ago•

9 replies

DeadlyRemix

❔ Generics

Random randomClass = new Random();
List<Type> aList = new List<Type> { new A(), new B(), new C() };
int randomInteger = randomClass.Next(3);
Type type = aList[randomInteger];
typeFunc<type>();
static void typeFunc<T>() where T : A
{
    Console.WriteLine("This worked");
}

public class A
{
    
}
public class B : A
{

}
public class C : A
{

}

Random randomClass = new Random();
List<Type> aList = new List<Type> { new A(), new B(), new C() };
int randomInteger = randomClass.Next(3);
Type type = aList[randomInteger];
typeFunc<type>();
static void typeFunc<T>() where T : A
{
    Console.WriteLine("This worked");
}

public class A
{
    
}
public class B : A
{

}
public class C : A
{

}

How is this done? Thanks

❔ Generics

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