2 replies

Obtaining and Refining an Option from a Generic String using Schema

I'm trying to obtain an

Option

Option

Option

Option from a generic string and refine it as an union

a

a,

b

b and

c

c. If empty I get

Option.None

Option.None

Option.None

Option.None. I already have a combinator

string

string

string

string ->

Option<string>

Option<string>

Option<string>

Option<string> when empty.

export const optionFromEmptyString = pipe(
  Schema.string,
  Schema.transform(
    Schema.optionFromSelf(Schema.string),
    Option.liftPredicate((s) => s.length > 0),
    (s) => Option.getOrElse(s, () => ""),
  ),
);

export const optionFromEmptyString = pipe(
  Schema.string,
  Schema.transform(
    Schema.optionFromSelf(Schema.string),
    Option.liftPredicate((s) => s.length > 0),
    (s) => Option.getOrElse(s, () => ""),
  ),
);

export const optionFromEmptyString = pipe(
  Schema.string,
  Schema.transform(
    Schema.optionFromSelf(Schema.string),
    Option.liftPredicate((s) => s.length > 0),
    (s) => Option.getOrElse(s, () => ""),
  ),
);

export const optionFromEmptyString = pipe(
  Schema.string,
  Schema.transform(
    Schema.optionFromSelf(Schema.string),
    Option.liftPredicate((s) => s.length > 0),
    (s) => Option.getOrElse(s, () => ""),
  ),
);

Can I leverage

Schema.union

Schema.union

Schema.union

Schema.union/

Schema.literal

Schema.literal

Schema.literal

Schema.literal without having to map every value in

transform

transform

transform

transform after my combinator?

Obtaining and Refining an Option from a Generic String using Schema

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