Can I name the result of an anonymous traversal without moving the traverser?

I can currently do the following:

Graph graph = TinkerFactory.createModern();

GraphTraversalSource gts = AnonymousTraversalSource.traversal().withEmbedded(graph);

gts.V().hasLabel("person")
        .has("name", "josh")
        .where(__.out().has("name", "ripple"))
        .project("rippleCreatorName", "rippleName", "rippleLang")
        .by("name")
        .by(__.out().has("name", "ripple").values("name"))
        .by(__.out().has("name", "ripple").values("lang"))
        .toList();

Graph graph = TinkerFactory.createModern();

GraphTraversalSource gts = AnonymousTraversalSource.traversal().withEmbedded(graph);

gts.V().hasLabel("person")
        .has("name", "josh")
        .where(__.out().has("name", "ripple"))
        .project("rippleCreatorName", "rippleName", "rippleLang")
        .by("name")
        .by(__.out().has("name", "ripple").values("name"))
        .by(__.out().has("name", "ripple").values("lang"))
        .toList();

I wish I could do something like this instead:

Graph graph = TinkerFactory.createModern();

GraphTraversalSource gts = AnonymousTraversalSource.traversal().withEmbedded(graph);

gts.V().hasLabel("person").has("name", "josh")
        .let("ripple", __.out().has("name", "ripple"))
        .project("rippleCreatorName", "rippleName", "rippleLang")
        .by("name")
        .by(__.select("ripple").values("name"))
        .by(__.select("ripple").values("lang"))
        .toList()

Graph graph = TinkerFactory.createModern();

GraphTraversalSource gts = AnonymousTraversalSource.traversal().withEmbedded(graph);

gts.V().hasLabel("person").has("name", "josh")
        .let("ripple", __.out().has("name", "ripple"))
        .project("rippleCreatorName", "rippleName", "rippleLang")
        .by("name")
        .by(__.select("ripple").values("name"))
        .by(__.select("ripple").values("lang"))
        .toList()

What would you recommend to me? I only want to do __.out().has("name", "ripple") once, because in my project this filter is much longer so there is considerable repeated code.

Solution:

You could perhaps play around with store ``` gremlin> g.V().hasLabel("person"). ......1> has("name", "josh"). ......2> where(__.out().has("name", "ripple").store('a'))....

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4 Replies

Solution

kelvinl2816•13mo ago

You could perhaps play around with store

gremlin> g.V().hasLabel("person").
......1>       has("name", "josh").
......2>       where(__.out().has("name", "ripple").store('a')).
......3>       project("rippleCreatorName", "rippleName", "rippleLang").
......4>       by("name").
......5>       by(select('a').unfold().values("name")).
......6>       by(select('a').unfold().values("lang"))

==>[rippleCreatorName:josh,rippleName:ripple,rippleLang:java]

gremlin> g.V().hasLabel("person").
......1>       has("name", "josh").
......2>       where(__.out().has("name", "ripple").store('a')).
......3>       project("rippleCreatorName", "rippleName", "rippleLang").
......4>       by("name").
......5>       by(select('a').unfold().values("name")).
......6>       by(select('a').unfold().values("lang"))

==>[rippleCreatorName:josh,rippleName:ripple,rippleLang:java]

danielcraig23•13mo ago

Thanks Kelvin, is .store('a') equivalent to .aggregate(local, 'a')? I'd like to avoid deprecated traversal steps

kelvinl2816•13mo ago

It is but I'm arguing we should never remove store and likewise reverse its deprecated status. I think store is more discoverable than (aggregate,local...)

danielcraig23•13mo ago

I agree

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Can I name the result of an anonymous traversal without moving the traverser?