S
SolidJS•8mo ago
AesthetiCoder

splitProps default value

how can i define the default value of a prop with split prop, for example the "loader" prop is optional i want tha make it true by default, but it is undefined 
const [ local, rest ] = splitProps(props, ['loader'])
const [ local, rest ] = splitProps(props, ['loader'])
yes i can use a ternary and validate the value but i want to set the default value if it is possible 
  local.loader ? true : false
  local.loader ? true : false
1 Reply
REEEEE
REEEEE•8mo ago
use mergeProps 
props = mergeProps(props, {loader: false})
const [ local, rest ] = splitProps(props, ['loader'])
props = mergeProps(props, {loader: false})
const [ local, rest ] = splitProps(props, ['loader'])
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