createStore default value with anonymous function

In react I would do something like:

const [array, setArray] = useState(() => {
  /* some computation */
  return [...data];
});

const [array, setArray] = useState(() => {
  /* some computation */
  return [...data];
});

Can I do something similar with solid?

3 Replies

REEEEE•7mo ago

I personally haven't seen that before in React 🤔 But you could just call the function immediately.

const [array, setArray] = createStore((() => {
  /* some computation */
  return [...data];
})());

const [array, setArray] = createStore((() => {
  /* some computation */
  return [...data];
})());

itsyoboieltr•7mo ago

thats exactly what I ended up doing, but it looks soo ugly :DD btw, to justify the use case: I am getting the queried data from the solid-query cache, and want it to be available as the default state of the store. But this data is not always available of course, it is only available if the cache already has an entry. This is the current solution I ended up doing:

  const [rows, setRows] = createStore(
    (() => {
      const data = queryClient.getQueryData<(typeof query)['data']>(
        queryKey(),
      );
      return data ? doComputation(data) : [];
    })(),
  );

  const [rows, setRows] = createStore(
    (() => {
      const data = queryClient.getQueryData<(typeof query)['data']>(
        queryKey(),
      );
      return data ? doComputation(data) : [];
    })(),
  );

(it is not a derived state, because I need to be able to set it later, so I also need a setter. It is a store (vs a signal) because it is an array)

mdynnl•7mo ago

react provides that callback api because it has to provide it or else the initialization code will be running along with the component. but in solid, a component only initializes once so there's no point doing that.

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createStore default value with anonymous function