C#•7mo ago

creating a new type

how do Integers for example do it, that they are a struct under the hood but instead of calling a constructor like

int i = new int(0);

int i = new int(0);

they can be assigned like

int i = 0;

int i = 0;

8 Replies

IKryxxᵈᵉᵛ•7mo ago

and can the user replicate this?

exokem•7mo ago

Primitive types like int are special cases that I assume are handled by the C# compiler It isn't really possible to do much custom syntax unless you want to write a preprocessor or something

IKryxxᵈᵉᵛ•7mo ago

shite thanks

exokem•7mo ago

You can create custom types, but the syntax will use the new keyword like you have in the first line

cap5lut•7mo ago

there is also implicit/explicit conversion:

MODiX•7mo ago

cap5lut

sharplab.io (click here)

Example e = 5;
Console.WriteLine(e);
public readonly struct Example {
    private readonly int value;
    public Example(int value) {
        this.value = value;
    }
    public override string ToString() => $"Exaample({value...
    public static implicit operator Example(int value) => ...
}

Example e = 5;
Console.WriteLine(e);
public readonly struct Example {
    private readonly int value;
    public Example(int value) {
        this.value = value;
    }
    public override string ToString() => $"Exaample({value...
    public static implicit operator Example(int value) => ...
}

React with ❌ to remove this embed.

cap5lut•7mo ago

⤴️ will print Exaample(5) thats basically like casting, if that was explicit instead of implicit u would have to write Example e = (Example)5; its basically a casting operator override

Thinker•7mo ago

Also about ints, I the int constructor is never called when you do int i = 0;. Again ints are special.

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creating a new type