Retrieving the token from router context into an useGraphQL() wrapper around useQuery()
I tried to write and useQuery() wrapper so I can inject the logged user token.
import request from "graphql-request";
import { type TypedDocumentNode } from "@graphql-typed-document-node/core";
import { useQuery, type UseQueryResult } from "@tanstack/react-query";
import { HASURA_ENDPOINT } from "../utils/config";
import { useRouteContext } from "@tanstack/react-router";
export function useGraphQL<TResult, TVariables>(
document: TypedDocumentNode<TResult, TVariables>,
...[variables]: TVariables extends Record<string, never> ? [] : [TVariables]
): UseQueryResult<TResult> {
const { authClient } = useRouteContext({ from: "__root__" });
return useQuery({
queryKey: [(document.definitions[0] as any).name.value, variables],
queryFn: async ({ queryKey }) => {
const token = authClient.GetTokenSilentlyOptions();
if (token === null) {
throw new Error("Token is null");
}
const requestHeaders = {
authorization: Bearer ${token},
};
request(HASURA_ENDPOINT, document, queryKey[1] ? queryKey[1] : undefined, requestHeaders);
},
});
}
My router is like this
const rootRoute = rootRouteWithContext<{
authClient: Auth0Client;
queryClient: QueryClient;
}>()({
component: Layout
})
const patientRoute = new Route({
getParentRoute: () => authRoute,
path: '/patients',
component: PatientPage
})
My patient page is
export const PatientsPage = () => {
const { data, isPending, isError } = useGraphQL(PatientListRouteQuery, null);
I'm getting this erro
Invariant failed: useMatch("root") is being called in a component that is meant to render the '/auth/patients' route. Did you mean to 'useMatch("root", { strict: false })' or 'useRoute("root")' instead?3 Replies
passive-yellowOP•2y ago
Should I be getting this root context as thats the one with the context?
extended-salmon•2y ago
Just as it says. You must set strict to false because the useRouteContext call is inside a reusable component.
Of course this is really a router question
passive-yellowOP•2y ago
Thanks mate