Resource with another name besides "$record".

How can I use another variable name in my EditRecord class, other than "$record"? I get an error when I try to do this in the

getPages()

getPages()

method:

            'edit' => Pages\EditLocation::route('/{location}/edit'),

            'edit' => Pages\EditLocation::route('/{location}/edit'),

I guess it's looking for record specifically. However, I have a class that checks for a "location" route in the request and I need it to specifically check this. OR I need it to be able to see if

{record}

{record}

is an instance of

Location

Location

, but it seems that

{record}

{record}

is just a string or an Int, so I don't think that's possible. If anyone knows a way around this, that would be helpful.

Dennis Koch•1/15/24, 4:53 PM

I don't think you can change that, because it's looking for

$record

$record

in the mount method of the Livewire components

Jon MasonOP•1/15/24, 4:56 PM

that's unfortunate...maybe it's not doable, but it would be great it if also accepted a Model instance instead of just a string|int.

Dennis Koch•1/15/24, 4:56 PM

What do you mean?

$record

$record

is a model instance

Jon MasonOP•1/15/24, 5:04 PM

hmm...I thought I remembered the mount method accepting a string or an int.

My situation is that I have the concept of "locations" in my app, where a user can select a location and then functionality related to that specific location becomes available.

so my route would be like .

I have a "CheckSession" middleware, where I make sure that nothing goes wrong, like the location isn't stored in the session, or something like that:

If the route was named "location", or "1009" was an instance of

Location

Location

then I could do the above check if it's an instance of

Location

Location

. But doing , could be anything..

Jon MasonOP•1/15/24, 5:06 PM

I think I'll just have to check within my

LocationResource

LocationResource

, but I was hoping to be able to just check this universally within the middleware.

awcodes•1/15/24, 7:38 PM

$record is inferred so you should still be able to check its instanceof