Zod•6mo ago

shadi - hey everyone, i've been struggling with...

hey everyone, i've been struggling with building a recursive zod schema. I tried following the docs: https://github.com/colinhacks/zod?tab=readme-ov-file#recursive-types but still can't figure it out for my use case. here is what I'm trying to achieve:

const BranchSchema = z.object({
  prompt: BranchPromptSchema, // regular object schema
  branches: z.array(ConfigSchema),
});

const ConfigSchema = z.union([
  z.object({
    name: z.string(),
    branch: BranchSchema,
    actions: z.undefined(),
  }),
  z.object({
    name: z.string(),
    branch: z.undefined(),
    actions: z.array(ActionSchema),
  }),
]);

const BranchSchema = z.object({
  prompt: BranchPromptSchema, // regular object schema
  branches: z.array(ConfigSchema),
});

const ConfigSchema = z.union([
  z.object({
    name: z.string(),
    branch: BranchSchema,
    actions: z.undefined(),
  }),
  z.object({
    name: z.string(),
    branch: z.undefined(),
    actions: z.array(ActionSchema),
  }),
]);

thanks in advance 🙏

Solution:

You have to manually type either direction of the types, for example: ```ts const ActionSchema = z.object({ ... }); const BranchPromptSchema = z.object({ ... });...

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2 Replies

Solution

Sikari•6mo ago

You have to manually type either direction of the types, for example:

const ActionSchema = z.object({ ... });

const BranchPromptSchema = z.object({ ... });

const BranchSchema = z.object({
  prompt: BranchPromptSchema,
  branches: z.lazy(() => z.array(ConfigSchema)),
});

type Config = {
  name: string;
  branch: z.infer<typeof BranchSchema>;
  actions: undefined;
} | {
  name: string;
  branch: undefined;
  actions: z.infer<typeof ActionSchema>[];
};

const ConfigSchema: z.ZodType<Config> = z.union([
  z.object({
    name: z.string(),
    branch: BranchSchema,
    actions: z.undefined(),
  }),
  z.object({
    name: z.string(),
    branch: z.undefined(),
    actions: z.array(ActionSchema),
  }),
]);

const ActionSchema = z.object({ ... });

const BranchPromptSchema = z.object({ ... });

const BranchSchema = z.object({
  prompt: BranchPromptSchema,
  branches: z.lazy(() => z.array(ConfigSchema)),
});

type Config = {
  name: string;
  branch: z.infer<typeof BranchSchema>;
  actions: undefined;
} | {
  name: string;
  branch: undefined;
  actions: z.infer<typeof ActionSchema>[];
};

const ConfigSchema: z.ZodType<Config> = z.union([
  z.object({
    name: z.string(),
    branch: BranchSchema,
    actions: z.undefined(),
  }),
  z.object({
    name: z.string(),
    branch: z.undefined(),
    actions: z.array(ActionSchema),
  }),
]);

shadi•6mo ago

thanks alot, that worked perfectly!

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shadi - hey everyone, i've been struggling with...