How to update the state of a paged query manually?

My items are fetched from multiple sources and combined into one sorted list in a RQ store, where each source is a group, so I need to update the cache manually at the sorted index. Should I just use

onSuccess

onSuccess

to do this? how do I prevent the default append that RQ does on response?

Example:

const response = ['dog', 'cat', 'bird', /* new type */ 'car', 'truck', 'ship', /* new type */ 'apple', 'orange', 'lemon']

// Then, user clicks on "load more animals" and the API will query page-2 for just animals, so cache should be updated like this:
oldDataDraft.splice(4, 0, ...newAnimals)

const response = ['dog', 'cat', 'bird', /* new type */ 'car', 'truck', 'ship', /* new type */ 'apple', 'orange', 'lemon']

// Then, user clicks on "load more animals" and the API will query page-2 for just animals, so cache should be updated like this:
oldDataDraft.splice(4, 0, ...newAnimals)

TanStack•2y ago•

15 replies

rubber-blue

How to update the state of a paged query manually?

My items are fetched from multiple sources and combined into one sorted list in a RQ store, where each source is a group, so I need to update the cache manually at the sorted index. Should I just use

onSuccess

onSuccess

to do this? how do I prevent the default append that RQ does on response?

Example:

const response = ['dog', 'cat', 'bird', /* new type */ 'car', 'truck', 'ship', /* new type */ 'apple', 'orange', 'lemon']

// Then, user clicks on "load more animals" and the API will query page-2 for just animals, so cache should be updated like this:
oldDataDraft.splice(4, 0, ...newAnimals)

const response = ['dog', 'cat', 'bird', /* new type */ 'car', 'truck', 'ship', /* new type */ 'apple', 'orange', 'lemon']

// Then, user clicks on "load more animals" and the API will query page-2 for just animals, so cache should be updated like this:
oldDataDraft.splice(4, 0, ...newAnimals)

How to update the state of a paged query manually?

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