deep-jade

How can I show success on client using server action?

I am trying to useForm method. I want to show some nice UI when the form submits correctly. I am using NextJS and server actions. In my useForm config, I am trying to do this:

    onSubmit: async (test) => {
      console.log('T', test)
      if (!state.success) {
        enqueueSnackbar('Failed to create manual application.', {
          variant: 'error',
        })
        return
      }
      enqueueSnackbar('Successfully created manual application.', {
        variant: 'success',
      })
      setOpen(false)
    },

    onSubmit: async (test) => {
      console.log('T', test)
      if (!state.success) {
        enqueueSnackbar('Failed to create manual application.', {
          variant: 'error',
        })
        return
      }
      enqueueSnackbar('Successfully created manual application.', {
        variant: 'success',
      })
      setOpen(false)
    },

But the state is old, so I think I'm looking at the wrong object? My server action for example would return {success: true/false}

15 Replies

deep-jadeOP•2y ago

omg, do I just have to have a useEffect with state as a dependency? seems to work fine, but would be nice if there was a way I can do it in the config of useForm

like-gold•2y ago

No, you do not. Try adding your {success: true} in your server action, then add a useActionState to get the config

deep-jadeOP•2y ago

@crutchcorn hmmm I thought I tried that, but ill check it out again. Thanks is it useFormState or useActionState? Can you show me an example of how you would implement that in the onSubmit function?

like-gold•2y ago

useFormState got renamed to useActionState I need to update the docs and a blog post I wrote

deep-jadeOP•2y ago

I have an error with useActionState, but I think I'm on the latest @next...

like-gold•2y ago

Huh, weird. Try the React 19 RC?

deep-jadeOP•2y ago

TypeError: (0 , react__WEBPACK_IMPORTED_MODULE_5__.useActionState) is not a function or its return value is not iterable

TypeError: (0 , react__WEBPACK_IMPORTED_MODULE_5__.useActionState) is not a function or its return value is not iterable

regardless, if I figure that out, is it just as simple as doing this?

  const [state, action] = useActionState(
    createManualApplication,
    formFactory.initialFormState
  )

  const { Subscribe, handleSubmit, Field } = useForm<{
    businessName: string
    emailAddress: string
    phoneNumber: string
    applicationFile: File | null
  }>({
    defaultValues: {
      businessName: '',
      emailAddress: '',
      phoneNumber: '',
      applicationFile: null,
    },
    transform: useTransform(
      (baseForm: FormApi<any, any>) => mergeForm(baseForm, state),
      [state]
    ),
    onSubmit: async (values) => {
      console.log('S', state)
    },
  })

  const [state, action] = useActionState(
    createManualApplication,
    formFactory.initialFormState
  )

  const { Subscribe, handleSubmit, Field } = useForm<{
    businessName: string
    emailAddress: string
    phoneNumber: string
    applicationFile: File | null
  }>({
    defaultValues: {
      businessName: '',
      emailAddress: '',
      phoneNumber: '',
      applicationFile: null,
    },
    transform: useTransform(
      (baseForm: FormApi<any, any>) => mergeForm(baseForm, state),
      [state]
    ),
    onSubmit: async (values) => {
      console.log('S', state)
    },
  })

I just look at the state var from the hook?

like-gold•2y ago

You might wanna add an if in the mergeForm To conditionally handle the merge from the server in case it returns non form data But otherwise yeah

deep-jadeOP•2y ago

I think I have to review the mergeForm stuff, I mostly just ripped that from the example Is TSForm still a rather new product from TS? Also, I think useActionState is only available in the newest react, so I'll probably still try and useFormState. Do you think the same thing would fix there? I originally had that, but the state in the onSubmit was One behind (the first submit it would have initial data, second submit would have the response from the server action)

deep-jadeOP•2y ago

yeah so this:

    transform: useTransform(
      (baseForm: FormApi<any, any>) => {
        console.log('Transform', baseForm)
        console.log('useTransform state:', state)
        return mergeForm(baseForm, state)
      },
      [state]
    ),
    onSubmit: async (values) => {
      console.log('onSubmit', state)
    },

    transform: useTransform(
      (baseForm: FormApi<any, any>) => {
        console.log('Transform', baseForm)
        console.log('useTransform state:', state)
        return mergeForm(baseForm, state)
      },
      [state]
    ),
    onSubmit: async (values) => {
      console.log('onSubmit', state)
    },

has this console output when I submit

deep-jadeOP•2y ago

so the onSubmit is still old, but the transformState is correct, is the merge incorrect? @crutchcorn hate to ping direct, but would love to put a pin in this! I would be open to making relevnat suggestions to documentation 🙂

deep-jadeOP•2y ago

@crutchcorn to make my example a bit more verbose, I am using the same code from the TanStack Form documentation, with the server validation of age. Let me know how I can change the code to have an updated state, without needing a useEffect.

deep-jadeOP•2y ago

code:

import Client, { formFactory } from './client'

export async function myAction(prev: unknown, formData: FormData) {
  return await formFactory.validateFormData(formData)
}

export default async function Page() {
  return (
    <div className="container mx-auto py-10">
      <Client />
    </div>
  )
}

import Client, { formFactory } from './client'

export async function myAction(prev: unknown, formData: FormData) {
  return await formFactory.validateFormData(formData)
}

export default async function Page() {
  return (
    <div className="container mx-auto py-10">
      <Client />
    </div>
  )
}

'use client'

import {
  FormApi,
  createFormFactory,
  mergeForm,
  useTransform,
} from '@tanstack/react-form'
import { useFormState } from 'react-dom'
import { myAction } from './page'
import { useEffect } from 'react'

export const formFactory = createFormFactory({
  defaultValues: {
    firstName: '',
    age: 0,
  },
  onServerValidate({ value }) {
    if (value.age < 12) {
      return 'Server validation: You must be at least 12 to sign up'
    }
  },
})

export default function Client() {
  const [state, action] = useFormState(myAction, formFactory.initialFormState)

  const { useStore, Subscribe, handleSubmit, Field } = formFactory.useForm({
    transform: useTransform(
      (baseForm: FormApi<any, any>) => mergeForm(baseForm, state),
      [state]
    ),
    onSubmit: async (values) => {
      console.log('On submit state', state)
    },
  })

  useEffect(() => {
    console.log('Use Effect state', state)
  }, [state])

  const formErrors = useStore((formState) => formState.errors)

  return (
    <form action={action as never} onSubmit={() => handleSubmit()}>
      {formErrors.map((error) => (
        <p key={error as string}>{error}</p>
      ))}

     ...
    </form>
  )
}

'use client'

import {
  FormApi,
  createFormFactory,
  mergeForm,
  useTransform,
} from '@tanstack/react-form'
import { useFormState } from 'react-dom'
import { myAction } from './page'
import { useEffect } from 'react'

export const formFactory = createFormFactory({
  defaultValues: {
    firstName: '',
    age: 0,
  },
  onServerValidate({ value }) {
    if (value.age < 12) {
      return 'Server validation: You must be at least 12 to sign up'
    }
  },
})

export default function Client() {
  const [state, action] = useFormState(myAction, formFactory.initialFormState)

  const { useStore, Subscribe, handleSubmit, Field } = formFactory.useForm({
    transform: useTransform(
      (baseForm: FormApi<any, any>) => mergeForm(baseForm, state),
      [state]
    ),
    onSubmit: async (values) => {
      console.log('On submit state', state)
    },
  })

  useEffect(() => {
    console.log('Use Effect state', state)
  }, [state])

  const formErrors = useStore((formState) => formState.errors)

  return (
    <form action={action as never} onSubmit={() => handleSubmit()}>
      {formErrors.map((error) => (
        <p key={error as string}>{error}</p>
      ))}

     ...
    </form>
  )
}

like-gold•2y ago

@Tyler hold off on our SSR usage. It leaks server code to the client, which was news to me. We'll need to revisit the API some other time

deep-jadeOP•2y ago

ooooooh okay, I've seen that issue. Thanks for the heads up

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How can I show success on client using server action?

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