3 replies

Understanding `Schema.declare` Function's Use of `unknown` for `decode`/`encode` Inputs

Liam Butler-Lawrence · 2024-06-05T01:45:48.628Z

Why does the `Schema.declare` function require handling the `decode`/`encode` input as an `unknown`?

Why does the

Schema.declare

Schema.declare

function require handling the

decode

decode

encode

encode

input as an

unknown

unknown

Understanding `Schema.declare` Function's Use of `unknown` for `decode`/`encode` Inputs - Effect Community