iTeachChem•2y ago

Magnetostatics

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iTeachChem Helper•6/16/24, 11:50 PM

@Gyro Gearloose

iTeachChem Helper•6/16/24, 11:50 PM

Note for OP

+solved @user1 @user2...+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.

OOpt Click to see attachment

Mr Xes⅔•6/17/24, 12:57 AM

this is a really good qn, i saw this case on a physics galaxy video... i dont remember its soln still but ill link the video for you if you wanna check it out
https://www.youtube.com/watch?v=gNoaUQaVDvM&list=PLYVDsiuOZP5p6fmdFyKhc2di1AMQZZEaU&index=26\

OptOP•6/17/24, 12:57 AM

Thanks. Will give it a look.

Mr Xes⅔•6/17/24, 1:05 AM

Apologies. The video has the case of a ring with angular speed, not a sphere.
But sir gave: Effect Current = Q.(omega)/2pi

OptOP•6/17/24, 1:05 AM

@KaiZên the one he discusses is the magnetic field inside the sphere

OptOP•6/17/24, 1:05 AM

I managed to solve that. Rather easy integration. But what is troubling me is the magnetic field outside. It's non-negligible. So no, "Solenoid ke bahar magnetic field zero ho jaata hai" business here.

Deleted User•6/17/24, 1:20 AM

@Opt have they asked B field function at distance r along the rotational axis itself?

Deleted User•6/17/24, 1:20 AM

or radially?

DDeleted User @Opt have they asked B field function at distance r _along_ the rotational axis ...

OptOP•6/17/24, 1:21 AM

It's asked as a function of the position vector r

Deleted User•6/17/24, 2:50 AM

yup so its radial.....

MMr Xes⅔ Apologies. The video has the case of a ring with angular speed, not a sphere. Bu...

Deleted User•6/17/24, 2:51 AM

but also consider this:- here it is asked as a radial function....so its not that direct

OptOP•6/17/24, 2:57 AM

I did, but it's the magnetic vector potential, not the field

Deleted User•6/17/24, 2:57 AM

vector potentiel? potentiels are scalar right?

OptOP•6/17/24, 2:57 AM

No no, vector potential

OptOP•6/17/24, 2:58 AM

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OptOP•6/17/24, 2:58 AM

And it's spherical coordinates

OptOP•6/17/24, 2:58 AM

I think the person who sent me this question was high or they just randomly made it up

DDeleted User _vector_ potentiel? potentiels are scalar right?

OptOP•6/17/24, 3:00 AM

The magnetic vector potential is defined as the vector field the curl of which is the magnetic field.

OOpt The magnetic vector potential is defined as the vector field the curl of which i...

Deleted User•6/17/24, 3:01 AM

oh wait u meant in that terms-

Deleted User•6/17/24, 3:01 AM

i did read that in griffiths

( i thought you meant standard potentiel term

)

DDeleted User i did read that in griffiths 😄 ( i thought you meant standard potentiel term ☠...

OptOP•6/17/24, 3:01 AM

This is from Griffiths lol

Deleted User•6/17/24, 3:01 AM

griffith op

OptOP•6/17/24, 3:01 AM

The solution I just sent I mean. Not the question

DDeleted User griffith op 🔥

OptOP•6/17/24, 3:02 AM

True.

OOpt The solution I just sent I mean. Not the question

Deleted User•6/17/24, 3:02 AM

yeah. if you are looking for on axis B field its easy enough just integrate all the rings.....

OptOP•6/17/24, 3:02 AM

Yeah it's a hell of an issue outside the shell.

OOpt True.

Deleted User•6/17/24, 3:02 AM

good to see someone using griffith! give it a read (especially where they derive the amperes circuital law eqn from biot-savart law!) its entire rollercoaster of visualisation man...

OOpt Yeah it's a hell of an issue outside the shell.

Deleted User•6/17/24, 3:03 AM

especially radial i would say

DDeleted User good to see someone using griffith! give it a read (especially where they derive...

OptOP•6/17/24, 3:03 AM

Ye it is. I started with Feynman's Lectures, then moved onto Griffiths.

OOpt Ye it is. I started with Feynman's Lectures, then moved onto Griffiths.

Deleted User•6/17/24, 3:03 AM

you are on right track man

OptOP•6/17/24, 3:04 AM

Feynman's Lectures Vol.3 remains untouched lol

OptOP•6/17/24, 3:04 AM

Spin samajh hi nahi aaraha. No matter how I try to understand

OOpt Spin samajh hi nahi aaraha. No matter how I try to understand

Deleted User•6/17/24, 3:05 AM

ill try to link a source.

OptOP•6/17/24, 3:05 AM

One more thing. In this question, can we consider the magnetic moment and use the electric dipole comparison method?

OOpt One more thing. In this question, can we consider the magnetic moment and use th...

Deleted User•6/17/24, 3:06 AM

i was thinking the same thing tbh....it should work considering a sphere of rings is just a distorted solenoid..

OptOP•6/17/24, 3:07 AM

But the solenoid radius is varying.

OptOP•6/17/24, 3:07 AM

This is just nightmare fuel you have to admit

OOpt But the solenoid radius is varying.

Deleted User•6/17/24, 3:07 AM

yes thats why i said "distorted"

OOpt This is just nightmare fuel you have to admit

Deleted User•6/17/24, 3:08 AM

i do admit

(mathmetically)

@Ameya²•6/17/24, 3:08 AM

the thing is the magnetic field is not uniform at every point at a dist r.
amperes law doesn't seem to be useful and neither is integration wala method useful ig.
as the field varies everywhere

Deleted User•6/17/24, 3:08 AM

let me try once k?