21 replies

TypeScript Function for Schema.Struct Without Context

I'd like to write a function which accepts a

Schema.Struct

Schema.Struct

Schema.Struct

Schema.Struct, but with no context, but I'm not sure how. Basically, fill in the

???

???

???

???:

const structsWithNoContextOnly = <S extends ???>(s: S) => {
  s.fields // where this works without type errors
  Schema.decodeUnknownSync(s)(null) // and this too
}

const structsWithNoContextOnly = <S extends ???>(s: S) => {
  s.fields // where this works without type errors
  Schema.decodeUnknownSync(s)(null) // and this too
}

const structsWithNoContextOnly = <S extends ???>(s: S) => {
  s.fields // where this works without type errors
  Schema.decodeUnknownSync(s)(null) // and this too
}

const structsWithNoContextOnly = <S extends ???>(s: S) => {
  s.fields // where this works without type errors
  Schema.decodeUnknownSync(s)(null) // and this too
}

What's the best way to do this?

TypeScript Function for Schema.Struct Without Context

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