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I am running this simple code to scrape a website - Firecrawl
F
Firecrawl
•
2y ago
•
3 replies
Dhruv Patel
I am running this simple code to scrape a website
from firecrawl import FirecrawlApp
api
_key
= os
.environ
[
"FIRECRAWL
_API
_KEY
"
]
app
= FirecrawlApp
(api
_key
=api
_key
)
url
=
"
https://atharvacoe.ac.in/
"
scraped
_data
= app
.scrape
_url
(url
)
pprint
(scraped
_data
)
the response i am getting is
PS
C
:
\Users
\DHRUV PATEL
\Desktop
\SCOGO
\firecrawl
\firecrawl
> python test
.py
Traceback
(most recent call last
)
:
File
"
C
:
\Users
\DHRUV PATEL
\Desktop
\SCOGO
\firecrawl
\firecrawl
\test
.py
"
, line 32
, in
<module
>
scraped
_data
= app
.scrape
_url
(url
)
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
^
File
"
C
:
\Users
\DHRUV PATEL
.
conda
\envs
\firecrawl
\Lib
\site
-packages
\firecrawl
\firecrawl
.py
"
, line 91
, in scrape
_url
self
.
_handle
_error
(response
,
'scrape URL
'
)
File
"
C
:
\Users
\DHRUV PATEL
.
conda
\envs
\firecrawl
\Lib
\site
-packages
\firecrawl
\firecrawl
.py
"
, line 317
, in
_handle
_error
raise requests
.exceptions
.HTTPError
(message
, response
=response
)
requests
.exceptions
.HTTPError
: Payment Required
: Failed to scrape URL
. Insufficient credits
even though i have 498 credits left
Atharva College of Engineering
AtharvaCOE
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