11 replies

Setting Default Value for Optional Field based on Required Fields in TypeScript Schema Class

hey there! I have this schema, where

name

name

name

name is optional and the other two fields are required

export class Round extends Schema.Class<Round>('Round')({
  name: Schema.optional(SchemaSchema.NonEmptyString),
  referenceSemester: Schema.Union(Schema.Literal(1), Schema.Literal(2)),
  referenceYear: Schema.Number.pipe(Schema.positive()),
}) {}

export class Round extends Schema.Class<Round>('Round')({
  name: Schema.optional(SchemaSchema.NonEmptyString),
  referenceSemester: Schema.Union(Schema.Literal(1), Schema.Literal(2)),
  referenceYear: Schema.Number.pipe(Schema.positive()),
}) {}

export class Round extends Schema.Class<Round>('Round')({
  name: Schema.optional(SchemaSchema.NonEmptyString),
  referenceSemester: Schema.Union(Schema.Literal(1), Schema.Literal(2)),
  referenceYear: Schema.Number.pipe(Schema.positive()),
}) {}

export class Round extends Schema.Class<Round>('Round')({
  name: Schema.optional(SchemaSchema.NonEmptyString),
  referenceSemester: Schema.Union(Schema.Literal(1), Schema.Literal(2)),
  referenceYear: Schema.Number.pipe(Schema.positive()),
}) {}

I would like to make the default value of

name

name

name

name be

${referenceYear}/${referenceSemester}

${referenceYear}/${referenceSemester}

${referenceYear}/${referenceSemester}

${referenceYear}/${referenceSemester} if

name

name

name

name is not present when I call

Round.make

Round.make

Round.make

Round.make, but I could not find a way to do it using

Schema.optionalWith

Schema.optionalWith

Schema.optionalWith

Schema.optionalWith. I'm not sure if that should be done with encode/decode or if there's something specific for this scenario. Can anyone help me on that?

Setting Default Value for Optional Field based on Required Fields in TypeScript Schema Class

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