12 Replies
@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.NaNH2 is a really strong base. Eliminates HBr to give you alkyne
base hai
yep
Even though it's a vinyl bromide, NaNH2 does not care
red hot iron tube for ring formation after that
Cyclic trimerisation yup
You get mesitylene I'm pretty sure
Option b
base
dehydrohalogenation
yesyes
tri methyl benzene
at meta positions
Ooooooo I was removing just Br
Wait why is it taking H with Br
Uhhh it's basically like alc.KOH but stronger.
So that mechanism
Proton gets abstracted, electron pairs kicks the Br out to form triple bond iirc
I legit just got home I'll look into this in an hour (ghaar aake kaam jo mil jaata hai gharwalo ka)
Ok got it dude
Thanks a lot
+solved @Opt @Nimboi @Dexter
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