Kinematics Doubt
in this problem, why can't we take the height as 2 m while calculating the time of flight for finding umin?
If the take height as 2m then time of flight increases, which overall decreases the horizontal velocity
10 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.t = √(2•∆h/g)
You need to take the height difference
Not the total height
You can think of it like this.
Given that I launched the ball off a 1m high platform, what velocity should it have such that it lands between √5 and 2√5 from the base of the platform?
But what if someone throws the marble in such a way that it directly reaches the bottom of the box instead of aiming for the top? Wouldn't that path require the least possible velocity?
this will be the least velicty then
if u can understand
it cant phase throught the walls
thats why we took 1 m
if we take 2 and calc lowest it will phase through walls
Quantum tunneling looking at you:
lmao was thinking the same
flash and quantum tunneling
oooh, makes sense...my dumb brain didn't take of that
thanks
+solved @Gamertug
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