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@Dexter
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.here we go
4/9 of them would give iodoform test
4th, 6th, 7th and 9th one...
carbon with '=O' or '-OH' should also be bonded with a CH3 to give iodoform test
2nd answer but-2-ene
Second one gives
2,4,6,7,9
1,3-diketones give haloform test
1st bhi dena chahiye ig
tautomerism
I heard somewhere
that resorcinol gives iodoform
Oh yeah it has H bond stability in ketone form
🤔
I guess you only sent that paper here
i remember vaguely
I remember sending a 1,3diketone question
Ok, resorcinol gives iodoform, given sufficient time. It's a very slow reaction.
Fir to bonus type ka question hua ye...
idk
maybe two answers
advanced does that alot
har saal controversial compounds dedete hai
😹😹
Bhaii wdym bonus q. Hone ka toh rusting v slow process hota h 😂
Lekin hmm mereko v yahi laga ki aromaticity kho dega
Toh kaafi unstable like hoga but fir ring strain v toh finally 0 ho jayega
wait but tautomerizing would mean giving up aromaticity
forget slow rate why would it give iodoform pretty much at all
There is always an equilibrium, even if it's heavily dominated by one side.
As soon as the smallest bit of the tautomer reacts, Le Chatelier principle comes into effect
yeah that makes sense
confusing as hell for a question tho
Wow bro but guess what I don't think le chatelier is applied when in 2 compounds is form n one is major n the other one as minor...by that logic every minor will become major ones😂
This isn't minor/major. This is keto/enol
Anyways got the solution...ppt form hoga isiliye forward jayegi
Ask me if u have any doubt otherwise closing it
+solved @Opt @Nimboi @Dexter
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