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@Apu
Note for OP
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i dont understand , how can u guarantee mid point will have integral solution
odd+odd=even, even+even=even logic.
she did 2x5 for all 3
that will also include odd + even + even
which is odd
or is there smth i dont understand
We are not adding the x, y and z components, we are only concerned with 2 x components, 2 y components...etc
oooh i get it nw
mb
Ah I see. Its just that you have taken the order of selection into account and hence, are getting an additional factor of 2.
I am sorry but I don't get it...can you explain it again pls
I mean let the points be (a,b,c) and (d,e,f). Ig the case (a,b,c),(d,e,f) amd (d,e,f)(a,b,c) are counted separately which should not be the case
ohhhhh
Got it thanks
+solved @SirLancelotDuLac
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