PnC/binomial, sum of choice function series
I don't really know where to start
12 Replies
@Apu
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Hint: Start of by writing C0-C1+C2...=0
1. Write the above down and write C11=C9, C12=C8...C20=C0 and so on
2. Now what you have is 2(C0-C1+C2-...+C10)-C10=0. So 2S=C10
oh I actually wrote down 4 standard results like this
let me send
completely forgot to send this
@SirLancelotDuLac can you confirm if this is correct tho I had a doubt for the longest time
didn't know who to ask either
Where is the doubt here?
is it all correct?
Seems correct to me.
let's goooooo
nice
my ass thought 20 was the power ir was raised to
nvm
i need to study this topic better
+solved SirLancelotDuLac
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