Electro

force on shell and charge is same first charge and shell will cover distance R/2 then charge is just inside shell , potential inside shell is 0 , acc is 0 they both travel with const Velocity for R distance , R by charge , R by shell Distance travelled by Charge = R + R/2 = 3R/2 this is the answer and const velocity for R distance , this also the answer but Pt of charge at start = KqQ/R and it wont just decrease linearly since shell is also moving , how will we find speed?
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iTeachChem Helper
@Gyro Gearloose
iTeachChem Helper
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.
Gamertug
GamertugOP5mo ago
we did the pt of Charge due to shell but wont we do pt of shell due to charge?
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SirLancelotDuLac
Potential due to interaction of 2 objects 1 and 2 is only counted once and not twice.
Gamertug
GamertugOP5mo ago
ic +solved @SirLancelotDuLac
iTeachChem Helper
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