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, rotate
@Apu
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1st question 5th part
Both even and odd. (Apologies for the bad handwriting.)
Basically the idea is simplification of the first part,
$e^{-\sqrt{\abs{ln({x})}}}=e^{\frac{-\abs{ln({x})}}{\sqrt{\abs{ln({x})}}}}=e^{\frac{ln({x})}{\sqrt{\abs{ln({x})}}}}={x}^{\frac{1}{\sqrt{\abs{ln({x})}}}}$
SirLancelotDuLac
So the first part simplifies to zero.
And the second part is zero (Since the first thing is not defined at integers, i.e., when fractional part is zero).
okkk got it thanx
+solved @SirLancelotDuLac
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