Magnetism doubt
Shouldn't the force be 0 as the loop is closed and therefore, dl vector (displacement vector) is 0
Pls ignore the stuff I have written with the blue pen
35 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Magnetic field is varying but it's given that it's a constant B near the periphery which is why I feel like the net force should be 0
In reality this type of magnetic field is not possible as it violates maxwell laws....(div.B=0)....fir the sake of question/illustration u can consider it and solve this...
I see
Thanks
?
the force is acting perpendicularly
dl is just a quantity here not a vector
Hm?
its a vector for each element
Wdym it's not a vector
Dl is the displacement
the direction of force is perpendicular to the plane of the irng
if you write it in vector form its integral of i(dl cross B)
which cant be exactly integrated over
with normal integration im not aware of vector calculus
each element dl is experiencing a force say df perpendicular to the ring
This is given on the next page
The force is 0?
the b is radial
B is perpendicular to the plane in this case but the reasoning is the same
Integration of dl vector is 0
in that question
@Monishrules
thats for if b is uniform
the magnetic field is uniform over the entire plane vectorially
but in that situation its constant in magnitude only
The magnetic field in the question I originally asked is also uniform
Read it carefully
B near the periphery of the ring is same
the magnitude is the same
Ah you mean the direction is diff
the diagram illustrates that B is perpendicular at all points
yes
True. I noticed that after you pointed it out
So the integral cannot be evaluated, right? (At least within the bounds of the syllabus)
yes
so we just take the vector part out of the integral and since its all in the same direction
we integrate around the loop magnitude wise
But why didn't that yield zero
As ultimately dl was left within the integral
As dl (displacement vector) should be 0
But then why is net force in a current carrying loop in a uniform electric field zero
It's zero because dl vector evaluates to 0
I don't understand what you're trying to say
dF= BIdL but I don't understand what exactly happens when we integrate it
@Fusion
Yes?
b vector likhna chaiye tha left me
sorry i have to go you can ping someone else
if theres confusion
Alright
Thanks
Sorry about how late I am, but did you get this?
we ok here? u understand it? or still some doubt?
We alright
+solved @Monishrules
+solved
+solved @Monishrules
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