19 Replies
@Gyro Gearloose
Note for OP
+solved @user1 @user2... to close the thread when your doubt is solved. Mention the users who helped you solve the doubt. This will be added to their stats.Whats the ans? 2?
Ha
@integralofe^2v
Hol up just few mins js woke up rn
The vcom comes to rest after first collision so in 1 dumbbell both particles will perform SHM and after 1/2 time period they will collide again and dumbbell will reverse velocities
uhh i didnt understand much
Did u understand that when the first balls collide ( right ball from left dumbell and vice versa) there velocities will change direction cuz elastic collision?
yeah
ye me samjh gaya
Okay then see the velocity of center of mass, did u get it how its zero right? Since mv + m(-v) /2m which is zero
yeah yaha tk i got it
second colission ka thoda smjh kam aya
Okay what does that mean? The whole dumbell is at rest right after collision? So the two particles will kind of execute SHM
right
Now after half a time period of SHM meaning the spring was inutially relaxed, theb it was maximally compressed ( shortest dist bw 2 particles) then it stretches again but this time velocity reverses in direcgion for both particles
As it happens in SHM right?
oh alright samjh gaya
actually wo time period wli baat se thoda confusion aagya tha
but me samjh gaya apka point
Ohh nicee
thanks u so much
+solved @integralofe^2v
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