Keep type name when using generic

export declare type AnyBrand = Brand<unknown, any>;

export declare type Brand<Base, Branding, ReservedName extends string = "__type__"> = Base & {
    [K in ReservedName]: Branding;
} & {
    __witness__: Base;
};

export function customArktypeBrand<TBrand extends AnyBrand>(validation: Type<string | number>): Type<TBrand> {
    return validation as unknown as Type<TBrand>;
}

const schema = type({
   id: customArktypeBrand<MyBrand>(type.number)
})

export const TranslationSchema = <T extends AnyBrand>(of: type.Any<T>) =>
    type({
        id: of,
        value: "string",
    });

const output = TranslationSchema(customArktypeBrand<MyBrand>(type.number));
type Output= typeof output.infer;

type Test = {
    id: {
        __type__: "myBrand";
    } & {
        __witness__: number;
    };
    value: string;
}

type Test = {
    id: MyBrand;
    value: string;
}