20 Replies
mene gp lia a/r^3, a/r, ar,ar3
And ar ko alpha=1/2 lia
Product of roots lia
,rotate
a=1 aya
r=1/2 so common ratio 1/4
Lekin agar a/r ko alpha lia to common ratio 4 ayega
Aisa kyu:uhh:
wait wait
bhai kyuki jo tumne GP li hai uska CR actually me r^2 hai shayad??
wait
kya
wait im eepy i think im just blabbering things now
Ha to mene bola na r=1/2 aya to common ratio 1/4
:uhh:
Yea I realise that and made the conclusion that I am eepy
So I go eep
Someone else maybe help or I come tommorow
Oh okay
@apu
Ohh I can't do that I guess
mod hi kr payege ig
Hmm I suppose
Yaar aana to same chahiye
Whi to ni arhe:uhh:
@SirLancelotDuLac can y check this one please:hmmm:
Okay, isme one of the roots is given as 1/2, so plug that to get m=170. After this, the roots are of form 1/r^3, 1/r, r and r^3.
Their sum is m/16
So (r+1/r)+(r+1/r)^3-3(r+1/r)=m/16
Which yields 8a^3-16a=85
(Where a is r+1/r)
Which yeilds t^3-8t=85, which on trial and error gives t=5
Which means 2a=5 or a=2.5
Which gives r+1/r=5/2
Which gives one of the roots as 2
After this the roots are 1/8,1/2,2 and 8
@Real potato
@SirLancelotDuLac bro ye solve to hogya tha
Mera doubt kuch or tha
Ye ki mene roots ko a/r^3 a/r ar and ar^3 mana
Fir alpha ko ar maan lia
Wha se mera common ratio 1/4 ara hai
But agar a/r ko alpha lia
To waha se 4 ara hai
Aisa kyu hora hai
Both are the same things. Ek mein 8,2,1/2,1/8 aayega and ek se 1/8,1/2,2,8
Wo me samjha but option me 4 given tha
I mean, 4 works. 1/4 works too.
Yea ig it does i was just confused due to the option
I mean even if we do by general approach taking gp as a,ar,ar^2 waha se bhi 4 or 1/4 ajata
Anyways thanks
+solved @SirLancelotDuLac
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