Generating FastCheck Arbitrary for Input Type Instead of Output Type
I'm noticing that Arbitrary.make for Schema<A, I, R> produces FastCheck.Arbitrary<A> - i have most use cases that call for FastCheck.Arbitrary<I> - is there an easy way to do this, or should i just split up my schema defs so i can pass the pre-transformed... is that even a reasonable thing to try and do?
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