10 Replies
@GyroGearloose
nahh didt work ok
@Moderator ping fijiks wale
@Apu
abey
ðŸ˜
ye math ka hai
ping gyrogearloose
kp/r^3 ??
yea
saw solution
but it was
weirdly worded
samjha hi nahi
how to thibnk
@Gyro Gearloose
this is faraday's cage
any charges enclosed by a conductor will produce surface charges such that no net field is experienced outside the conductor
hence the surface charges must cancel the electric field by anything inside
hence kp/r^3
OHHHHHH
kinda makes sense
conductor ke andar field has to be 0
so charges bhi aise hi banenge
ok so basically
E due to dipole + E due to induced charges = 0
+solved @hardcoreisdead @Monishrules
arey wah
+solved @hardcoreisdead @Monishrules
+solved @hardcoreisdead @Monishrules
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